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| Both sides previous revisionPrevious revisionNext revision | Previous revision | ||
| documentation:language_reference:objects:responsefunction:operations:sub [2024/12/22 16:16] – Maurits W. Haverkort | documentation:language_reference:objects:responsefunction:operations:sub [2025/11/20 04:20] (current) – external edit 127.0.0.1 | ||
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| <code Quanty Example.Quanty> | <code Quanty Example.Quanty> | ||
| a1 = {0, -1, | a1 = {0, -1, | ||
| - | b1 = { 0.2, 0.2, 0.2, 0.2} | + | b1 = { 0.2, 0.2, 0.3, 0.3} |
| G1 = ResponseFunction.New( {a1, | G1 = ResponseFunction.New( {a1, | ||
| Line 61: | Line 61: | ||
| <file Quanty_Output> | <file Quanty_Output> | ||
| { { 0 , -1 , 0 , 5 , 6 } , | { { 0 , -1 , 0 , 5 , 6 } , | ||
| - | { 0.1 , 0.1 , 0.15 , 0.05 } , | + | { 0.1 , 0.1 , 0.25 , 0.15 } , |
| name = G1 , | name = G1 , | ||
| mu = 0 , | mu = 0 , | ||
| Line 67: | Line 67: | ||
| </ | </ | ||
| - | The pole in $G_2$ at energy $-0.5$ is equally divided between the poles at $-1$ and $0$ in $G_1$, such that each of these residues is reduced by $0.2/ | + | The pole in $G_2$ at energy $-0.5$ is equally divided between the poles at $-1$ and $0$ in $G_1$, such that each of these residues is reduced by $0.2/ |
| ===== Table of contents ===== | ===== Table of contents ===== | ||
| {{indexmenu> | {{indexmenu> | ||