Differences

This shows you the differences between two versions of the page.

Link to this comparison view

Both sides previous revisionPrevious revision
Next revision
Previous revision
Last revisionBoth sides next revision
documentation:language_reference:functions:createfluorescenceyield [2016/10/10 09:41] – external edit 127.0.0.1documentation:language_reference:functions:createfluorescenceyield [2018/05/12 22:50] Maurits W. Haverkort
Line 4: Line 4:
 //CreateFluorescenceYield($O_1$,$O_2$,$O_3$,$\psi$)// calculates  //CreateFluorescenceYield($O_1$,$O_2$,$O_3$,$\psi$)// calculates 
 \begin{equation} \begin{equation}
-\frac{\mathrm{i}}{\pi}\int \langle \psi | O_2^{\dagger} \frac{1}{(\omega - \mathrm{i} \Gamma/2 + E_0 - O_1^{\dagger})} O_3^{\dagger} O_3\frac{1}{(\omega + \mathrm{i} \Gamma/2 + E_0 - O_1)} O_2 | \psi \rangle,+\frac{ \langle \psi | O_2^{\dagger} \frac{1}{(\omega - \mathrm{i} \Gamma/2 + E_0 - O_1^{\dagger})} O_3^{\dagger} O_3\frac{1}{(\omega + \mathrm{i} \Gamma/2 + E_0 - O_1)} O_2 | \psi \rangle,
 \end{equation} \end{equation}
 with $E_0 = \langle \psi | O_1 | \psi \rangle$. The spectrum is returned as a spectrum object. Please note that fluorescence yield is the expectation value of an Hermitian operator. The returned spectrum is thus completely real. Possible options are: with $E_0 = \langle \psi | O_1 | \psi \rangle$. The spectrum is returned as a spectrum object. Please note that fluorescence yield is the expectation value of an Hermitian operator. The returned spectrum is thus completely real. Possible options are:
Print/export